Ten most important Reasoning questions with answers for SSC CGL Exam
Ten Most Important Reasoning questions with answers for competitive exams of circles, box and other type with solutions have been discussed in this post . These types of problems are very helpful for cracking competitive exams like ssc cgl, ssc chsl and various Bank exams and many other similar exams.
Ten Reasoning questions with answers for competitive exams
Problem # 1
This box problem consist of four rows and four columns . And we have to find the value of question mark after studying the pattern of all the numbers in this box.
If we divide this box into two parts vertically then we can have the formula for these numbers written in this box . Because after careful observation we can see that the sum of both the numbers in left half in any particular row is equal to sum of both the numbers in right half in that particular row.
Formula:- (1st number + 2nd number ) = (3rd number + 4th number)
4 + 12 = 11 + 5 = 12 (Equal sum in both the half of 1st row)
6 + 7 = 10 + 3 = 13 (Equal sum in both the half of 2nd row)
8 + 9 = 10 + 7 = 17 (Equal sum in both the half of 3rd row)
7 + 5 = ? + 4 = 12 (Equal sum in both the half of 4th row) .
Hence ? = 12 - 4 = 8
? = 8
6 + 7 = 10 + 3 = 13 (Equal sum in both the half of 2nd row)
8 + 9 = 10 + 7 = 17 (Equal sum in both the half of 3rd row)
7 + 5 = ? + 4 = 12 (Equal sum in both the half of 4th row) .
Hence ? = 12 - 4 = 8
? = 8
Option (D)8 is correct option
Problem # 2
This circle consists of four quadrants and every quadrant consists of two numbers . Every quadrant have one numbers in outer part and one number in the inner part . To find the value of question mark "?" , we shall use two numbers which are in the inner part of adjoining sectors to calculate the value of the number which is in the outer part of every quadrant .
Formula :- Sum of the squares of two adjoining numbers in two inner sectors is equal to number in outer part.
1st Quadrant
2nd Quadrant
5² + 4² = 25 + 16 = 41
3rd Quadrant
4² + 2² = 16 + 4 = 20
4th Quadrant
2² + 3² = 4 + 9 = 13
Option (4)13 is correct option
Problem # 3
The number in any inner sector of this circle can be broken into two parts . 1st part can be taken as base of the number and 2nd part can be taken as the power of that number. And after writing it like this, the value of same number will be equal to the number in the outer part of same sector.
2nd Quadrant
53 ----> 5^3 = 125
3rd Quadrant
43 ----> 4³ = 64
4th Quadrant
25 ----> 2^5 = 32
1st Quadrant
Option (1) 27 is correct option
Problem # 4
This circle consists of four quadrants and every quadrant consists of two numbers . Every quadrant have one numbers in outer part and one number in the inner part . To find the value of question mark "?" , we shall use two numbers which are in the inner part of adjoining sectors to calculate the value of the number which is in the outer part of every quadrant .
3² + 5 = 9 + 5 = 14
5² + 9 = 25 + 9 = 34
9² + 2 = 81 + 2 = 83
2² + 3 = 4 + 3 = 7
Option (1)7 is correct option
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Problem # 5
This reasoning problem consists of three figures and every figure have five number associated to it . Four numbers are at the corner of each figure and one number is at the centre of the figure. Look at last figure ,it have ? in its centre . So the solution of this problem is to find the value of question mark using four numbers associated to it .
But the biggest problem is how to utilised these four numbers to get the value of this question mark?
Now watch carefully the 1st two figures . Since these figures have some values at middle position.
Now we have to find or search the formula for these four numbers in each figure to utilised them in any possible way to get middle or central number.
The same formula will be applicable to third figure to find out the value of question mark.
Formula :- Keep on doubling the every number to get next number starting from middle number.
Solution:-
1st figure
4 , (Middle number)
4 × 2 = 8
8 × 2 = 16,
16 × 2 = 32,
32 × 2 = 64
2nd figure
5 , (Middle number)
5 × 2 = 10
10 × 2 = 20,
20 × 2 = 20,
20 × 2 = 40
40 × 2 = 80
3rd figure
? , (Middle number)
? × 2 = 5 implies ? = 2.5
2.5 × 2 = 5,
5 × 2 = 10,
10 × 2 = 20.
20 × 2 = 40.
Option (4)2.5 is correct option
Problem # 6
This box problem consist of three rows and three columns. And we have to find the value of question mark after studying the pattern of all the numbers in this box.
Third number of every row is equal to the product of square of 1st number and square root of 2nd number.
Formula:- Square of 1st number × Square root of 2nd number
(3)2 × √49 = 9 × 7 = 63 ( Number in 1st row 3rd column )
(4)2 × √25 = 16 × 5 = 80 ( Number in 2nd row 3rd column )
(5)2 × √25 = 25 × 5 = 125 ( Number in 3rd row 3rd column )
(?)2 × 8 = 200
(?)2 = 200 ÷ 8
(?)2 = 25
? = 5
Option (A)125 is correct option
(4)2 × √25 = 16 × 5 = 80 ( Number in 2nd row 3rd column )
(5)2 × √25 = 25 × 5 = 125 ( Number in 3rd row 3rd column )
(?)2 × 8 = 200
(?)2 = 200 ÷ 8
(?)2 = 25
? = 5
Option (A)125 is correct option
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Problem # 7
This reasoning problem consists of three figures and every figure have five number associated to it . Four numbers are at the corner of each figure and one number is at the centre of the figure. Look at last figure ,it have ? in its centre . So the solution of this problem is to find the value of question mark using four numbers associated to it .
But the major problem is how to utilised these four numbers to get the value of this question mark?
Now watch carefully the 1st two figures . Since these figures have some values at middle position.
Now we have to find or search the formula for these four numbers in each figure to utilised them in any possible way to get middle or central number.
The same formula will be applicable to third figure to find out the value of question mark.
Formula :- Difference of Sum of three number in upper half and lower half is equal to the middle number in every figure.
( 4 + 2 + 7 ) - ( 3 + 1 ) = 13 - 4 = 9 (Middle Number in 1st star ).
( 3 + 3 + 5 ) - ( 4 + 2 ) = 11 - 6 = 5 (Middle Number in 2nd star).
( 6 + 9 + 2 ) - ( 4 + 3 ) = 17 - 7 = 10 (Middle Number in 3rd star).
Option (3)10 is correct option
Problem # 8
This reasoning problem consists of three figures and every figure have five number associated to it . Four numbers are at the corner of each figure and one number is at the centre of the figure. Look at last figure ,it have ? in its centre . So the solution of this problem is to find the value of question mark using four numbers associated to it .
But the main problem is how to utilised these four numbers to get the value of this question mark?
Now watch carefully the 1st two figures . Since these figures have some values at middle position.
Now we have to find or search the formula for these four numbers in each figure to utilised them in any possible way to get middle or central number.
The same formula will be applicable to third figure to find out the value of question mark.
Formula :- Difference of Product of three number in upper half and lower half is equal to the middle number in every figure.
(4 × 2 × 5 ) - ( 20 × 1 ) = 40 - 20 = 20 (Middle Number in 1st star).
(3 × 4 × 5 ) - ( 2 × 10 ) = 60 - 20 = 40 (Middle Number in 2nd star).
( 8 × 6 × 1 ) - ( 14 × 3 ) = 48 - 42 = 6 (Middle Number in 3rd star).
Option (3)6 is correct option
Problem # 9
This reasoning problem consists of three figures and every figure have five number associated to it . Four numbers are at the corner of each figure and one number is at the centre of the figure. Look at last figure ,it have ? in its centre . So the solution of this problem is to find the value of question mark using four numbers associated to it .
But the biggest problem is how to utilised these four numbers to get the value of this question mark?
Now watch carefully the 1st two figures . Since these figures have some values at middle position.
Now we have to find or search the formula for these four numbers in each figure to utilised them in any possible way to get middle or central number.
The same formula will be applicable to third figure to find out the value of question mark.
Formula :- Keep on doubling the every number to get next number starting from middle number.
3 × ( 4 + 5 + 6 ) = 3 × 15 = 45 ( Middle Number in 1st circle ) .
1 × ( 9 + 6 + 3 ) = 1 × 18 = 18 ( Middle Number in 1st circle ) .
7 × ( 5 + 2 + 8 ) = 7 × 15 = 105 ( Middle Number in 1st circle ) .
Option (3)105 is correct option
Problem # 10
In this pattern 1st number which is 520 can be written as sum of cube of 8 and 8 , 738 can be written as sum of cube of 9 and 9, 350 have been be written as sum of cube of 7 and 7. Similarly ? will be written as sum of cube of any number and the number itself.
8³ + 8 : 9³ + 9 : 6³ + 6 : 7³ + 7
6³ + 6 = 216 + 6 = 222
Option (2)222 is correct option
Ten Most Important Reasoning questions with answers for competitive exams of circles, box and other type with solutions have been discussed in this post . These types of problems are very helpful for cracking competitive exams like ssc cgl, ssc chsl and various Bank exams and many other similar exams. please feel free to comment your opinions.
