Most important Reasoning questions with answers which includes circle problems, box problems, circle problems, triangles problems for competitive exams like SSC CGL ,SSC CHSL ,CPO ,Bank exams and RRB NTPC etc have been explained in this post.

**Ten Important **Reasoning questions with answers for competitive exams

**Problem #1**

### This reasoning problem is a box problem of 4 rows and 3 columns, where the the value of question mark in last row we have to find.

**Formula :- **Sum of the squares of 1st two columns = Squares of 3rd column

**1st Row**

3² + 4² = 5²

➡ 9 + 16 = 25

➡ 25 = 25

L H S = R H S

**2nd Row**

6² + 8² = 10²

➡ 36 + 64 = 100

➡ 100 = 100

L H S = R H S

**3rd ****Row**

7² + 24² = 25²

➡ 49 + 576 = 625

➡ 625 = 625

L H S = R H S

**4th ****Row**

12² + ?² = 13²

➡ 144 + ?² = 169

➡ ?² = 169 -144

➡ ?² = 25 , Taking square root on both sides

? = 5

**Option (C)5 is correct option**

## Problem #2

### Formula :- Five less than the product of sum of two corner's numbers in each rectangle.

**1st Rectangle**

**2nd Rectangle**

{(21 + 1) × ( 3 + 2 ) } - 5 = (22 × 5) - 5 = 110 - 5 = 105

**3rd Rectangle**

{(62 + 5) × ( 1 + 1 ) } - 5 = ( 67 × 2) - 5 = 134 - 5 = 129 = ?

**Option (2)129 is correct option**

## Problem #3

This reasoning problem consists of three triangles and every triangle have four numbers ,three around the triangle and one in the centre of the triangle.

**Formula :-**Product of all the outer numbers = Middle numbers

### 1st Figure

5 × 6 × 4 = 120 ⇒1 + 2 + 0 = 3 ( Middle number in 1st triangle )

### 2nd Figure

6 × 7 × 5 = 210 ⇒2 + 1 + 0 = 3 ( Middle number in 2nd triangle )

### 3rd Figure

4 × 8 × 10 = 320 ⇒3 + 2 + 0 = 5 ( Middle number in 3rd triangle )

**Option (2)5 is correct option**

This reasoning problem consists of three squares and every squares have four small squares , And each small square contains a number in it. If we add all the numbers in each small square then we shall have total of 35 in each small square.

**Formula :- **Sum of all the numbers in a square = 35

### 1st Square

5 + 12 + 8 + 10 = 35

### 2nd Square

8 + 16 + 6 + 5 = 35

### 3rd Square

4 + 10 + ? + 15 = 35

29 + ? = 35

? = 35 - 6

? = 6

**Option (4)6 is correct option**

**Problem #5**

### 1st Quadrant:-

HCF ( Highest common Factor ) of 4 and 8 is 4

### 2nd Quadrant:-

HCF ( Highest common Factor ) of 3 and 5 is 1

### 3rd Quadrant:-

HCF ( Highest common Factor ) of 6 and 12 is 6

### 4th Quadrant:-

HCF ( Highest common Factor ) of 10 and 25 is 5

**Option (2)5 is correct option**

**Problem #6**

All the numbers which are around the circle in any figure do not have any role to make the number in centre of the circle. But all the digits of the central number in 1st figure are reversed, So in same way all the digits of the central number in 2nd figure will be reversed to get the central/middle number in the 3rd figure. Hence 6543 will be the value of question mark.

**Option (4)6543 is correct option**

**Problem #7**

Sum of all the numbers in any particular column are same for all column like

### Formula :- All Numbers in any columns have equal total.

[10 + 7](1st Column) = 17 = [9 + ? + 6](2nd Column) = [ 15 +2] = 17( 3rd Column) . Now calculating the value of ? from any two column.

→ ? = 2

**Option (1)2 is correct option**

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**End**

## **Problem #8**

Sum of square of three numbers in upper line is equal to the number in lower line in each figure.

**Formula :-**Sum of the squares of numbers in 1st row = Number in 2nd row

**1st Figure :-**

2² + 5² + 6² = 4 + 25 + 36 = 65

**2nd Figure :-**

6² + 8² + 9² = 36 + 64 + 81 = 81

**3rd Figure :-**

2² + 8² + 7² = 4 + 64 + 49 = 117

**Option (2)117 is correct option**

**Problem #9**

Sum of all the numbers in every row is 20.

2 + 3 + 7 + 8 = 20 ( Last Row )

4 + 7 + 9 = 20 ( 2nd Last Row )

11 + 9 = 20 ( 2nd Row )

Hence the value of "?" must be 20

**Option (4)20 is correct option**.

**Problem #10**

This

**Reasoning question have three triangles in it, And every triangle consists of four numbers around it , The middle number in each triangle can be written using the formula given below****Formula** :- b² - ( 1st side² - 2nd side²) = Middle number

**1st Triangle :-**

7² - ( 4² + 3²) = 49 - (16 + 9 ) = 49 -25 = 24 42

**2nd Triangle :-**

8² - ( 6² + 3²) = 64 - (36 + 9 ) = 64 - 45 = 19 91

**3rd ****Triangle**** :-**

9² - ( 5² + 3²) = 81 - (25 + 9 ) = 81 - 34 = 47 74

**Option (3)74 is correct option**.

## Conclusion

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