## SOME OF MY PUBLISHED POSTS ARE APPEARING HERE IN CHRONOLOGICAL ORDER

In this post I have shown here my some of previous published posts in chronological order.Let us discuss them one by one.

## Example : To Find the Square of Two Digits Numbers Ending with 5

Here I shall show how square of

**35**can be found quickly.

####
**Step 1**

when unit/(Right most) place of a number ends with 5

then place 25 as last two digits (i. e Right most ) of the result.

####
**Step 2**

Take the digit which is on the unit's place and multiply it with its successor (next digit from it), Here in this case the 1st two digits are 12, the product of 3 and its successor 4.

#### Step 3

The square of 35 = (3×4)(25)

= 1225

## Example

## To find Square of 65 and many more Examples

## To find the transpose of matrix

5

5

2

,then shift the elements which are in 2nd row to 2

-1

,then shift the elements which are in 2nd row to 2

^{nd}column as-1

-3

7

similarly shift all the elements which are in 3rd row to 3

^{rd}column as
4

2

8

And the matrix so obtained is the transpose matrix. We can check that same colour row have been transformed to same colour column

Now we shall take this example to find the transpose Matrix

## How to find the multiplication using short cut Method 52324 × 11= ?

2 Now add 0 to its neighbour 4 as 0 + 4 = 4

3 Now add 4 to its neighbour 2 as 4 + 2 = 6

4 Now add 2 to its neighbour 3 as 2 + 3 = 5

5 Now add 3 to its neighbour 2 as 3 + 2 = 5

6 Now add 2 to its neighbour 5 as 2 + 5 = 7

7 Place left most digit as it is = 5

8 Write the digits so obtained ( blue coloured) from top to bottom as right to left

#### So Answer will be 5,75,564

### How to Multiply 543423 × 11= ? and many more using short cut Method

##
**How to Multiply two numbers 98 and 96 nearer to 100**

98 × 96 = (98 - 4)(2×4) = (94)(08) = 9408 (Only in mind )Step 1

Consider both the numbers as Num 1 = 98 and Num2 = 96.

Subtract Num 1 from 100 and write its Result 1 as one place .

Also Subtract Num 2 from 100 and write its as Result 2 second place .

Result 2 = 100 - 96 = 4

Now multiply the results so obtained and mark it as Stepresult1.Stepresult1 = 4*2 = 8 = 08

**Step 2**

Subtract the result of Result 1 (blue Answer) from Num 2 i. e.(96 ).

Here we haveStepresult2 = 96-2= 94

Final Answer = (Ist two digits are Stepresult2)(2nd two digits are Stepresult1)

= 9408

The result so obtained i. e. 9408 is the answer of product of two numbers

## More Examples like 92 × 91 = ?

##
How to Differentiate f(x) = (cos x )^{sin x}

then it derivative will be

f '(x) = f(x) Diff (h(x))

⇒ f '(x) = f(x) [(log cos x) . Diff (sin x) + sin x Diff (log cos x)]

Therefore f '(x) = f(x) [(log cos x) . cos x + sin x (-sin x ) /cos x)]

Therefore f '(x) = (cos x )

^{sin x}[(log cos x) . cos x - sin x .tan x]

##
**Differentiate w.r.t. 'x'**** ****f(x) = cos x **^{sin x} + (sin x) ^{x}* *

**f(x) = cos x**

^{sin x}+ (sin x)^{x}

## What is Matrix

#### Matrix definition

A Matrix is a set of elements ( Numbers ) arranged in a particular numbers of Rows and columns in a rectangular table. Matrices inside parentheses ( ) or brackets [ ] is the matrix notation.

Here we have an examples of Matrices .

The elements which are written in horizontal lines are called Row and elements which are written in Vertical lines are called Column. In the matrix A above ↑ the elements 5, 3, -2 are written in Row wise whereas the elements 5,4,3 are written columns wise, Similarly the elements 4,-1,7 are written in Row wise whereas the elements 3,-1,4 are written columns wise .

##

Order Of a Matrix

If any matrix have "m" number of rows and "n" number of columns , then "m×n" will be the order of that matrix. It is also called matrix dimensions . For matrices given below ,

[ 5 6 -4 2 ] This matrix has 1×4 order,

3

[ 8 ] Matrix has 3×1 order ,

-2

[ -1 ] Matrix has 1×1 order.

And the matrices A,B,C and D above have 3×3 ,2 ×2 , 3×4 and 3×2 respectively, as Matrix A has 3 rows and 3 columns, matrix B has 2 rows and 2 columns, Matrix C has 3 Rows and 4 Columns Similarly Matrix D has 3 rows and 2 columns.

##

Elements of a matrix , Types of matrix ,

##
Equality of Matrices* *And Determinent

## Condition for Matrix Multiplication

Before multiplication of two matrices we have to check whether multiplication is possible or not , If it is possible then matrices will be multiplied to each other. Necessary condition for multiplication of two matrices is if " The number of columns in the first matrix is the same as the number of rows in the second matrix ". We must know different types of matrices ,Rows and Column.

### Note : The commutation may or may not be possible for multiplication of matrices, That is in some case AB = BA but In general AB is not equal to BA.

###
Example 1

2. Multiplication of 5 × 1 matrix with 1 × 2 matrix is also possible as it gives 5× 2 matrix as resultant Matrix.

3. Multiplication of 4 ×3 matrix with 2 × 3 matrix is NOT possible. Because red colour numbers 3 and 2 do not match .

### How to Multiply Matrices

To Solve the system of Linear Equations using 2×2 Matrix Method

x - 5y = 4

2x + 5y = −2

x - 5y = 4

2x + 5y = −2

Writing this system of equation in Matrix form

AX = B

where X = A-1 B------------------------(1)

And A-1 = (1/Det A ) ( Ad joint A)

Where

We need the inverse of

*A*, which we write as

*A*-1

Ad joint A = ( 5 5 -2 1 )

Co factor A = ( 5 −2 5 1 )

As we know the Ad joint Matrix of any matrix can be found by taking the transpose of the Co Factor matrix.

Now let us find the determinant of A

Therefore

*A*-1 Exists ,So

Now putting the value of inverse of Matrix A in equation (1)

Now putting the elements of Matrix X , and

By the equality of two Matrices ,their elements in respective positions are equal to each others,

Hence x= 2/3 and y = -2/3

x - y + z = 4

2x + y - 3z = 0

x + y + z = 2

---------------------------------------------------------------------------------

**How to multiply Two Matrices**

Let us take one example to Multiply 2×3 and 3×2 Matrices ,The order of resultant matrix will be 2 × 2.

A11 element will be 4×(-3)+1×5+4×6 = -12+5+24 =17

A12 element will be 4×1+1×6+4×4 = 4+6+16 = 26

A21 element will be 2×(-3)-5×5+7×6 = -6-25+42 = 11

A22 element will be 2×1+(-5)×6+7×4 = 2-30+28 = 0

Since the resultant Matrix 2× 2 as follows

HOW TO MULTIPLY TWO MATRICES || PRODUCT OF TWO MATRICES

HOW TO MULTIPLY TWO MATRICES || PRODUCT OF TWO MATRICES

## Solving the Quadratic Equation

### 1 Factorisation Method

### 2 Completing the Square

### 3 Quadratic Formula

Completing the Square

1 Shift the constant term to right hand side of equal sign.

2 Complete the square in left side and add the term which is missing and adjust the added term on the right side.

3 Equate the Left hand term to Right hand term.

Let us consider a Quadratic Equation

*9x*2 – 15x + 6 = 0

To make the complete square add the missing term (b)2 and subtract the same term

(3

*x)*2 – 2*3x *(5/2)+ (5/2*)*2– (5/2*)*2 +6 = 0
{3x-(5/2)

*}*2 -(25/4)+6 = 0
{3x - (5/2)

*}*2 -(1/4) = 0
{3x-(5/2)

*}*2 = (1/4) Taking square roots
3x - (5/2) = (1/2) or 3x-(5/2) = - (1/2)

3x = (1/2)+(5/2) or 3x = -(1/2) + (5/2)

3x = 6/2 or 3x = 4/2

x = 1 or 3x = 2

x = 1 or x = 2/3

The roots of the given equation are 1 and 2/3

## Conclusion

In this post I have discussed some of my post published earlier in chronological order . If this post helped you little bit, then please share it with your friends to benefit them, comment your views on it and also like this post to boost me and to do better, and also follow me on my Blog .We shell meet in next post till then Bye .