Ten most important questions of Reasoning Analogy in missing numbers in various figures
Ten most important questions of missing number in Reasoning Analogy in various figures. These types of problems are very very important for the exams like SSC CGL ,SSC CHSL , RRB NTPC and many other similar competitive exams.
PROBLEM # 1
Since in 1st row we can write 3, 2 and 4 numbers to get 10 like this
( 3 × 2 ) + 4 = 6 + 4 = 10 (The number in last column of 1st row )
And in 2nd row ( 4 × 3 ) + 5 = 12 + 5 = 17, (The number in last column of 2nd row )
In 3rd row ( 5 × 4 ) + 6 = 20 + 6 = 26 ,(The number in last column of 3rd row )
Similarly ( 6 × 5 ) + 7 = 30 + 7 = 37 , (The number in last column of 4th row )
So " ? " Will be replaced by 37 .
Therefore correct option will be (D)
PROBLEM # 2
Let us find relation between 3 and 18 , if we double the square of 3 ,we shall have 18.
2 × ( 3^2) = 2 × 9 = 18 (The number in last column of 1st row )
And in 2nd row if we double the square of 4 ,we shall have 32
2 × ( 4^2) = 2 × 16 = 32, (The number in last column of 2nd row)
In the same way incresing the number one by one then third ,fourth and fifth columns can be calculated like this
2 × ( 5^2) = 2 × 25 = 50 (The number in last column of 3rd row )
2 × ( 6^2) = 2 × 36 = 72 (The number in last column of 4th row )
2 × (7^2) = 2 × 49 = 98 (The number in last column of 5th row )
Therefore correct option will be (C)
PROBLEM # 3
As the sum of first and second number in first and second rows in any particular column is equal to third element in that particular column so to get the value of " ? " . Differentiate first and second numbers column wise to get third number as follows.
56 - 12 = 44,
78 - 30 = 48 ,
65 - ? = 14 ➡️ ? = ? = 65 - 14 = 51
Therefore correct option will be (C)
PROBLEM # 4
Answer can be split into two parts, 1st part can be obtained by multiplying two given numbers and second part can be obtained by adding these two numbers .
1st row 5 × 3 = 15 and 5 + 3 = 8 so 5 , 3 = 158
2nd row 9 × 1 = 9 and 9 + 1 = 10 so 9 , 1 = 9103rd row 8 × 6 = 48 and 8 +6 = 14 so 8 , 6 = 4814
4th row 4 × 4 = 16 and 4 + 4 = 8 so 4 , 4 = 168.
5th row 7 × 3 = 21 and 7 + 3 = 10 so 7 , 3 = 2110
So ? Will be replaced by 2110.
Therefore correct option will be (A)
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PROBLEM # 5
Formula a*b = (a × b) + (b - 1)
This the sum of two numbers , out of two ,1st number is product of two given numbers and second is the number one less than 2nd given number.
3*2 = (3 × 2) + (2 - 1) = 6 + 1 = 7
5*4 = (5 × 4) + (4 - 1) = 20 + 3 = 23
7*6 = (7 × 6) + (6 - 1) = 42 + 5 = 47
9*8 = (9 × 8) + (8 - 1) = 72 + 7 = 79
10*9 = (10 × 9) + (9 - 1) = 90 +8 = 98
Therefore correct option will be (C)
PROBLEM # 6
Suppose we have three numbers a , b and c then
Formula for this puzzle is = (a × b) + b or b(a + 1)
Put a = 2 and b = 6 in above formula ,we get
1st Line = (2 × 6) + 6 = 12 + 6 = 18
Put a = 4 and b = 20 in above formula to get 2nd line,we get
(4 × 20) + 20 = 80 + 20 = 100
Put a = 5 and b = 21 in above formula to get 3rd line,we get
(6 × 21) + 21 = 126 + 21 = 147
So required and correct answer will be 6
PROBLEM # 7
If in every row ,we add 1st and 3rd column and then multiply the sum with 2nd column, we shall have number in 4th column .
If we consider three numbers a , b and c and start calculation by Formula = (a × b) + (b × c) or b(a + c) --------(1)
To get 1st line , put a = 1 , b = 2 and c = 3 in (1) , we get
1st Line = (1×2) + (2×3) =2 + 6 = 8
To get 2nd line , put a = 2 , b = 3 and c = 4 in (1) , we get
2nd Line = (2×3) + (3×4) = 6 + 12 = 18
To get 3rd line , put a = 3 , b = 4 and c = 5 in (1) , we get
3rd Line = (3×4) + (4×5) = 12 + 20 = 32
To get 4th line , put a = 4 , b = 5 and c = 6 in (1) , we get
4th Line = (4×5) + (5×6) = 20 + 30 = 50
Similarly Last line can be calculated by putting a = 5 , b = 6 and c = 7 in (1) , we get
Last line = (5×6) + (6×7) = 30 + 42 = 72
Therefore correct option will be (D)
PROBLEM # 8
Case 1
If we choose 1st number from 5 then look at the pattern opposite to given smaller number
5 × 3 = 15
8 × 3 = 24
12 × 3 = 36
In this pattern we can conclude 12 ×3 = 36
Case 2
If we choose 1st number from ? then look at the opposite to given smaller number
? × 3 = 12
5 × 3 = 15
8 × 3 = 24
Therefore ? will be replaced by 4.
Hence 4 × 3 = 12
PROBLEM # 9
This circle can be divided into two parts , 1st part containing the number 4 ,5 ,6 and 7 and second part containing 7 , 9 ,11 and ?. Now study the opposite number of 4 which is 7 . Then study the relation between other numbers and its opposite number ,we find difference between 4 and 7 is 3 , difference between 5 and 9 is 4 , difference between 6 and 11 is 5 . so in this pattern we can find difference between ' ? ' and 7 must be 6 .
7 - ? = 2 means ? = 5
7 - 4 = 3
9 - 5 = 4
11 - 6 = 5 , the difference is increased by 1 everytime .
? - 7 = 6 means ? = 13
Either 5 or 13 should be the required number, but 5 is not given in any option.
So ? Will be replaced by 13 which is the required answer
Therefore correct option will be (4)
PROBLEM # 10
We shall try every possible relation between different numbers given either row wise or column wise . It is found that there is no relation if we consider First row .
After elemination of 1st row we can develop a relation between 2nd ,3rd and 4th row which is multiplying the 2nd and 3rd numbers then double it to get 4th number column wise .
2 × (7 × 4 ) = 2 × 28 = 56
2 × ( 15 × 6 ) = 2 × 90 = 180
2 × ( 8 × ? ) = 80
So ? = 5Therefore correct option will be (B)
We shall try every possible relation between different numbers given either row wise or column wise . It is found that there is no relation if we consider First row .
After elemination of 1st row we can develop a relation between 2nd ,3rd and 4th row which is multiplying the 2nd and 3rd numbers then double it to get 4th number column wise .
2 × (7 × 4 ) = 2 × 28 = 56
2 × ( 15 × 6 ) = 2 × 90 = 180
2 × ( 8 × ? ) = 80
So ? = 5
Therefore correct option will be (B)
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