## Ten Latest tricky and logical Questions in box and circle reasoning for SSC CGL And SSC CHSL Exams

Ten Most Important tricky and logical Questions of Reasoning of box and circles problems with solutions are discussed in this post. . These types of problems are very helpful for cracking competitive exams like ssc cgl, ssc chsl and various Bank exams and many other similar exams .

** ****Problem #1**

# This circle is divided into eight parts and each part is composed of three numbers . In each numbers are in outer part of the circle and one number is in the inner part of the circle. If we multiply both the numbers which are in the outer part of the circle and then add one to it then this resultant number will in the inner part of the opposite circle.

**Therefore Correct option is (3)**

**Problem # 2**

**1st Method**

**multiply both the numbers which are in the outer part of the circle and then add two to it**then this resultant number will in the inner part of the opposite circle.

**Therefore Correct option is (4)**

**2nd Method**

**Therefore Correct option is (4)**

**Problem # 3**

**add these two simultaneous numbers then reverse the order of the result so obtained then this number will be equal to the number in the small circle opposite to both these numbers .**

**Therefore Correct option is (C)**

**Problem # 4**

Taking the difference of two consecutive terms in clockwise direction and analyse the difference , this difference always increases with the increment of 4.

**Therefore Correct option is (2)**

**Problem # 5**

**check the greater of the numbers which are in the outer part of the circle and**then this resultant number will in the inner part of the opposite circle.

Max (17,14) = 17 (Number in the inner part of the circle in 4th quadrant )

Max (18,13) = 18 (Number in the inner part of the circle in 3rd quadrant )

Max (5,3) = 5 (Number in the inner part of the circle in 2nd quadrant )

Max (4,8) = 8 = ? (Number in the inner part of the circle in 1st quadrant )

**Therefore Correct option is (2)**

**Problem # 6**

**four**parts and if we divide sum of all the digits in its outer part with number of parts then result will be the middle number.

**five**parts and if we divide sum of all the digits in its outer part with number of parts then result will be the middle number.

**six**parts and if we divide sum of all the digits in its outer part with number of parts then result will be the middle number.

**Hence option (3) is correct answer**

**Problem # 7**

### In 1st triangle

### In 2nd triangle

### In 3rd triangle

**Therefore Correct option is (4)**

**Problem # 8**

**Therefore Correct option is (B)**

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**Problem # 9**

**Therefore Correct option is (1)**

**Problem # 10**

**multiply both the numbers which are in the outer part of the circle and then divide the resultant so obtained with 4**then this resultant number will in the inner part of the opposite circle.

**(Number in the inner part of the circle in 3rd quadrant )**

**= ? (Number in the inner part of the circle in 1st quadrant )**

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Ten Most Important tricky and logical Reasoning of box and circles problems with solutions were discussed in this post. . These types of problems are very helpful for cracking competitive exams like ssc cgl, ssc chsl and various Bank exams and many other similar exams . Feel free to share your opinion regarding this post in comment box.

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