## Missing number series questions and answers, Missing Number Series Questions for SBI Clerk

Ten most important Missing number series questions and answers, Number Series Questions for SBI Clerk ,SBI PO with solution , for SSC GL , SSC CHSL , RRB NTPC and other competitive Exams have been discussed in this post. These types of series questions are asked in many other competitive exams like SI, CPO and various entrance exams.

## Problem #1

**Formula :- **

**Every term is the product of its two preceding terms.**

2nd number = 3

**Option (4)6561 is correct option**

## Problem #2

This problem is a series problem where we have to find the value of question mark using all its previous terms means by analysing the trend of all its terms whether they are in increasing order or decreasing order. This reasoning problem can be solved by two method . we shall discuss both these methods one by one.

**Method #1 **

35 -15 = 20 (Here difference of 1st and 2nd term is 20)

63 - 35 = 28 (Here difference of 2nd and 3rd term is 20 + 8 = 28, i.e. 8 more than previous difference)

99 -63 = 36 (Here difference of 3rd and 4th term is 28 + 8 = 36, i.e. 8 more than previous difference)

143 - 99 = 44 (Here difference of 4th and 5th term is 36 + 8 = 44, i.e. 8 more than previous difference)

? - 143 = 52 (Here difference of 5th and 6th term must be 44 + 8 = 52, i.e. 8 more than previous difference)

⇒ ? = 52 + 143 = 195

**Option (2)195 is correct option**

**Method #2**

All these terms are one less than perfect squares of even numbers.

4² - 1 = 16 -1 = 15** **

6² - 1 = 36 -1 = 35** **

8² - 1 = 64 -1 = 63** **

10² - 1 = 100 -1 = 99

12² - 1 = 144 -1 = 143

14² - 1 = 196 -1 = 195** **

**Option (2)195 is correct option**

## Problem #3

**Option (3)223 is correct option**

## Problem #4

**Option (2)1285 is correct option.**

## Problem #5

These numbers are in binary number system. So 1st of all convert these numbers to decimal number system.

11(binary number system) = 3 (decimal number system) .

100(binary number system) = 4 (decimal number system)

111(binary number system) = 5 (decimal number system)

Similarly

1000(binary number system) = 6 (decimal number system)

**Option (2)1000 is correct option**

## Problem #6

This reasoning problem is a series problem where we have to find the value of question mark using all its previous terms means by analysing the trend of all its terms whether they are in increasing order or decreasing order.

(9 × 1) - 2 = 9 - 2 = 7 ( 2nd Number )

(7 × 2) - 3 = 14 - 3 = 11 ( 3rd Number )

(11 × 3) - 4 = 33 - 4 = 29 ( 4th Number )

(29 × 4) - 5 = 116 - 5 = 111 ( 5th Number )

(111 × 5) - 6 = 555 - 6 = 549 ( 6th Number ) = value of question mark

**Option (4)549 is correct option**

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## Problem #7

**Option (2)50 is correct option**

## Problem #8

**Option (3)119 is correct option.**

## Problem #9

**Formula :- Sum of both digits of each numbers are same except one.**

**Option (2)30 is correct option**

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## Problem #10

**1st series**

**2nd series**

**Option (3)15 is correct option.**

## Your Queries

**(By Jai Singh Nayak)**

Missing number in series

1, 6, 26, _____ , 426

## **Formula **

** Next Term = (4 × Previous Term ) + 2.** 1st Term = 1

2nd Term = (4 × 1st Term ) + 2

2nd Term = (4 × 1 ) + 2

= 4 + 2

= 6

3rd Term = (4 × 2nd Term ) + 2

3rd Term = (4 × 6 ) + 2

= 24 + 2

= 26

4th Term = (4 × 3rd Term ) + 2

4th Term = (4 × 26 ) + 2

= 104 + 2

= 106

5th Term = (4 × 4th Term ) + 2

5th Term = (4 × 106 ) + 2

= 424 + 2

= 426

6th Term = (4 × 5th Term ) + 2

6th Term = (4 × 426 ) + 2

= 1704 + 2

= 1706

7th Term = (4 × 6th Term ) + 2

7th Term = (4 × 1706 ) + 2

= 6824 + 2

= 6826.

### By MD Kaif

Complete the series

1, 3, 4, 8, 15 , 27, ?

### Formula

**To find any term after 3rd Term = Sum of its previous three terms . **

4th term = 1st term + 2nd term + 3rd term = 1 + 3 + 4 = 8

5th term = 2nd term + 3rd term + 4th term = 3 + 4 + 8 = 15

6th term = 3rd term + 4th term + 5th term = 4 + 8 + 15 = 27

7th term = 4th term + 5th term + 6th term = 8 + 15 + 27 = 50 ( the value of question mark ).

**By Shavnam Sharma**

**Complete the series**

**343, 729, 1331, 2197, ?**

** Formula **

**Any Term = (n)³ ,where n is odd number greater than equal to 7**

Ten most important Missing number series questions and answers, Number Series Questions for SBI Clerk ,SBI PO with solution for SSC GL , SSC CHSL , RRB NTPC and other competitive Exams were discussed in this post. comment your valuable suggestions regarding this post and for further improvement.

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