## 10 Most Important Reasoning Problems of Circles with Solutions, How to Solve Reasoning Circle Problems

Ten Most Important Reasoning problems of circles with solutions. These types of problems are very helpful for cracking competitive exams like ssc cgl, ssc chsl and various Bank exams and many other similar exams .

**Problem # 1**

This circle consists of four quadrants and every quadrant consists of three numbers , And every quadrant have two numbers in outer part and 1 number is in the inner part . To find the value of question mark "?" , we shall use two numbers which are in the outer part to calculate the value of the number which is in the inner part of every quadrant .

#### 1st Quadrant

Square of 8 × Taking Power 4 of 3 = 64 × 81 = 5184

Now add all these digits 5 + 1 + 8 + 4 = 18

Now reversing the order of these digits obtained in previous step

18 <----> 81 The number in the inner part

#### 2nd Quadrant

Now add all these digits 6 + 0 + 0 + 2 + 5 = 13

Now reversing the order of these digits obtained in previous step

13 <----> 31 The number in the inner part

#### 4th Quadrant

Square of 8 × Taking Power 4 of 9 = 64 × 6561 = 419904

Now add all these digits 4 + 1 + 9 + 9 + 0 + 4 = 27

Now reversing the order of these digits obtained in previous step

27 <----> 72 The number in the inner part

#### 3rd Quadrant

Square of 7 × Taking Power 4 of 7 = 49 × 2401 = 117649

Now add all these digits 1 + 1 + 7 + 6 + 4 + 9 = 28

Now reversing the order of these digits obtained in previous step

28 <----> 82 The number in the inner part

**Option (1) is correct option.**

**Problem # 2**

This circle has been divided into eight sectors. Every sector consist of three numbers. To solve this problem **multiply both the numbers in any sector which are in the outer part and then add 1 to it ,the result so obtained is written in the inner part of the sector which is exactly opposite to this sector** .Continuing in this manner we shall have all the numbers placed accordingly. . Starting from the sector immediately to the right of question mark.

( 2 × 4 ) + 1 = 9 ( In the inner part of 5th sector )

( 3 × 7 ) + 1 = 22 ( In the inner part of 6th sector )

( 1 × 6 ) + 1 = 7 ( In the inner part of 7th sector )

( 5 × 2 ) + 1 = 11 ( In the inner part of 8th sector )

( 3 × 4 ) + 1 = 13 ( In the inner part of 1st sector )

( 2 × 9 ) + 1 = 19 ( In the inner part of 2nd sector )

( 2 × 2 ) + 1 = 5 ( In the inner part of 3rd sector )

( ? × 3 ) + 1 = 25 ( In the inner part of 4th sector )

Now we have to find the value of "?" like this

( ? × 3 ) + 1 = 25

? × 3 = 25 - 1

? × 3 = 24

? = 24/3

? = 8

**Hence option (2) is correct option**.

**Problem # 3**

**Hence option (4) is right answer.**

**Problem # 4**

__all the three digits of any number in both the circles then we shall get same result except in one number in both the circles. And that different result will be the odd one out in this problem.__

**add****In 1st circle**

**In 2nd circle**

**Hence option (4) is right answer.**

**Problem # 5**

Since this circle consists of four quadrants and every quadrant consists of three numbers ,two numbers are in outer part and one number is in the inner part ( triangle) . The number which is in the inner part (triangle) can be found using both the numbers which are in the outer part of the same quadrant by using the following formula

**.**

**(Difference of both numbers in the outer part) - ( difference of both the digits in the triangular parts ) = 1**

**1st Quadrants **

**2nd Quadrants **

**3rd Quadrants **

**4th Quadrants **

**So the correct option will be (1) .**

** Problem # 6**

__all the three digits of any number in both the circles then we shall get same result except in one number in both the circles. And that different result will be the odd one out in this problem.__

**add****In 1st circle**

**In 2nd circle**

**Hence option (4) is right answer.**

# Problem # 7

**Hence option (D) is correct option.**

** Problem # 8**

**four**parts and if we divide sum of all the digits in its outer part with number of parts then result will be the middle number.

**five**parts and if we divide sum of all the digits in its outer part with number of parts then result will be the middle number.

**six**parts and if we divide sum of all the digits in its outer part with number of parts then result will be the middle number.

**Hence option (3) is correct answer**

**Problem # 9**

**Therefore correct option will be (D) .**

**Problem # 10**

#### In 1st Sector

**In 2nd Sector**

**In 3rd Sector**

**In 4th Sector**

**So option (2) will be correct option**