## Wednesday 17 April 2019

### Most Important Reasoning questions with answers for competitive exams

Most Important Reasoning questions with answers for competitive exams of number analogy with solutions have been discussed in this post . These types of problems are very helpful for cracking competitive exams like ssc cgl, ssc chsl and various Bank exams and many other similar exams. please feel free to comment your opinions.

## What is next terms in the series ?

Let us solve next number in sequence puzzle
15, 29, 56, 108, 208, ????
Here 1st term is 15, To find out 2nd term if we multiply the 1st term With 2 and subtract 1 from it, i.e (15 × 2) -1  = 30 - 1= 29
To find 2nd term we have to multiply the previous term with 2 and subtract 2 (double the previous time) from it
i.e (29 × 2) - 2 = 58 - 2 = 56
To find 3rd term we have to multiply the previous term with 4   and subtract 2  (double the previous time) from it
i.e  (56 × 2) - 4 = 112 - 4 = 108
To find 4th term we have to multiply the previous term with 8 (double the previous time) and subtract 2 from it
i.e (108 × 2) - 8 = 216 - 8 =  208
Similarly 5th term can be calculated as
multiply the previous term with 2 and subtract  subtract 2 (double the previous time) from it
i. e.  (208 × 2) - 16 = 416 - 16 =  400
Next term (400×2) - 32 = 800 - 32 =  768

Next term  (768 × 2) - 64 = 1536  - 64 = 1472
Next term  (1472 × 2) - 128 = 2944 - 128  =2816
Or we can write it in another form as follows
15 + (15–1) = 15 + 14= 29
29 + (29–2) = 29 + 27 = 56
56 + (56–4) = 56 + 52 = 108
108 + (108–8) =108 + 100 = 208
208 + (208–16) = 208 + 192= 400
400 + (400–32) = 400 + 368 = 768

768 + (768–64= 768 + 704 = 1472

1472 + (1472-128) = 1472 + 1344 = 2816

And similarly this trend follows

## What’s the next number in the sequence 0, 2, 6, 12 , ?

We can get the answer in two  ways

## 1st Method

1 × (1–1) = 0 ( 1st term)

2 × (2–1) = 2 (2nd term)

3 × (3–1) = 6 (3rd term)

4 × (4–1) = 12 (4th term)

5 × (5–1) = 20 (5th term)

Next term must be  20
Similarly
6 × (6–1) = 30  (6th term)

7 × (7–1) = 42  (7th term)

## 2nd Method

1² – 1 = 1 - 1  = 0

2² –  2 = 4 - 2 = 2

3² – 3 = 9 - 3 = 6

4² – 4 = 16 - 4 = 12

5² – 5 = 25 - 5 =  20
Next term must be  20
Similarly

6² – 6 = 36 - 6 = 30

7² – 7 = 49 - 7=  42

## Can you solve this  Series: 30, 31, 28, 33, 26, 35, … What number should come next?

We can split this sequence into two series by picking alternate numbers from the given sequence.
30, 31, 28, 33, 26, 35, …
1st  one is 30,  28, 26, … and 2nd one is  31, 33,  35, …
Now after careful analysing the 1st sequence ,its next terms should be  with decrease of  2 ,we get other terms as follows
30,  28, 26, 24, 22 ,20 …
And after careful analysing the 2nd  sequence ,its next terms should be  with increase of  2 ,we get other terms as follows
31, 33,  35, 37, 39 ,41…

26 - 2 = 24.
So the text terms should be 30, 31, 28, 33, 26, 35, 24, 37, 22

24 is the next number in the required sequence.

## FINAL WORDS

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