## Reasoning questions with answers for competitive exams

Ten Most Important Reasoning questions with answers for ssc cgl and other competitive exams of box and other type with solutions have been discussed in this post .These types of problems are very helpful for cracking competitive exams like ssc cgl, ssc chsl and various Bank exams and many other similar exams.

# Ten Reasoning questions with answers for competitive exams

## Problem # 1

This box problem consist of five rows and four columns . Here in this problem we have to find the value of question mark which is lying in 2nd column of fourth row after studying the pattern of all the numbers in this box.This box problem consist of five rows and four columns . Here in this problem we have to find the value of question mark which is lying in 2nd column of fourth row after studying the pattern of all the numbers in this box.

Because after careful observation we can see that the difference of product of 1st and 4th rows from the sum of 2nd and 3rd rows in any particular column is equal to the number in fourth row in that particular column.

### Formula:-

**5th row = (1st row**

**×**

**4th**

**row**)**- (2n**

**d row**

**+**

**3rd**

**row**)

**(8 × 3) - (6 + 2) = 24 - 8 = 16 (Number in last row of 1st column).**

**1st column**

**3rd column**

(7 × 2) - (3 + 4) = 14 - 7 = 7 (Number in last row of 1st column) .

**4th column**

(5 × 9) - (2 + 8) = 45 - 10 = 35 (Number in last row of 1st column).

**2nd column**

(6 × 5) - (4 + 1) = 30 - 5 = 25 (Number in last row of 1st column). And this number will be the value of question mark.

**The correct Answer is option (3)25**

## Problem # 2

This box problem of reasoning consist of four rows and five columns . And we have to find the value of question mark which is lying in fourth row of

This box problem of reasoning consist of four rows and five columns . And we have to find the value of question mark which is lying in fourth row of

**fifth**column after studying the pattern of all the numbers in this box. Because after careful observation we can see that the difference of product of 1st and 4th

**column**from the sum of 2nd and 3rd**column**in any particular row is equal to the number in fifth**in that particular row.****column****Formula:- **

**Formula:-**

**5th Column = (1st****Column****×****4th****Column****)****- (2n****d****Column****+****3rd****)****Column**

**1st Row**(4 × 2) - (5 + 3) = 8 - 8 = 0 (Number in last column of 1st row.

**2nd Row**

(7 × 4) - (3 + 4) = 28 - 7 = 21 (Number in last column of 2nd row .

**3rd ****Row**

(6 × 5) - (4 + 4) = 30 - 8 = 22 (Number in last column of 3rd row).

**4th ****Row**

(9 × 5) - (6 + 5) = 45 - 11 = 34 (Number in last column of 4th row).

**The correct Answer is option (1)34**

## Problem # 3

**Formula:- Sum of both the numbers in outer circle of same octant + 1 = Number Opposite to both these numbers in inner circle**

(2 × 4) + 1 = 8 + 1 = 9(Opposite to both these numbers in inner circle).

(7 × 3) + 1 = 21 + 1 = 22(Opposite to both these numbers in inner circle).

(1 × 6) + 1 = 6 + 1 = 7(Opposite to both these numbers in inner circle).

(5 × 2) + 1 = 10 + 1 = 11(Opposite to both these numbers in inner circle).

(3 × 4) + 1 = 12 + 1 = 13(Opposite to both these numbers in inner circle).

(2 × 9) + 1 = 18 + 1 = 19(Opposite to both these numbers in inner circle).

(2 × 2) + 1 = 4 + 1 = 5(Opposite to both these numbers in inner circle).

(? × 3) + 1 = 25(Opposite to both these numbers in inner circle).

3 × ? = 25 - 1

3 × ? = 24

? = 24 ÷ 3? = 8

**Option (3)8 is corr**

**ect o**

**ption.**

## Problem # 4

In this reasoning problem study all these numbers . All these numbers are Prime numbers. But if we study all these numbers row wise in all the three boxes. Then these numbers are in increasing order. So if we write all the numbers written in all the three rows in a line as follows.

**1st Row **

2 , 3 , 5 , 7 , 11 , 13

**2nd Row **

17 , 19 , 23 , 29 , 31 , 37

**3rd Row **

41 , 43 , 47 , 53 , ? , 61

So prime number after 53 will be 59 and prime number before 61 will also be 59.

Hence the value of question mark will be 59.

**Option (2)59 is corr**

**ect o**

**ption.**

## Problem # 5

In this reasoning problem study all these numbers . All these numbers are Prime numbers. But if we study all these numbers box wise in all the three boxes. Then these numbers are in increasing order. So if we write all the numbers written in all the three rows in a line as follows.

**1st Box **

2 , 3 , 5 , 7 , 11 , 13

**2nd Box **

17 , 19 , 23 , 29 , ? , 37

**3rd Box **

41 , 43 , 47 , 53 , 59 , 61

So prime number after 29 will be 31 and prime number before 37 will also be 31.

Hence the value of question mark will be 31.

**Option (3)31 is corr**

**ect o**

**ption.**

## Problem # 6

17 - 5 = 12 ⇔ 21 (Reversing the orders of both the digits)(The number opposite in the circle between two selected numbers)

17 - 12 = 5 = 05 ⇔ 50 (Reversing the orders of both the digits)

31 - 12 = 19 ⇔ 91 (Reversing the orders of both the digits)

31 - 10 = 21 ⇔ 12 (Reversing the orders of both the digits)

11 - 10 = 1 = 01 ⇔ 10 (Reversing the orders of both the digits)

11 - 6 = 5 = 05 ⇔ 50 (Reversing the orders of both the digits)

8 - 6 = 2 = 02 ⇔ 20 (Reversing the orders of both the digits)

8 - 5 = 3 = 03 ⇔ 30 (Reversing the orders of both the digits)(The number opposite in the circle between two selected numbers, and this will be the value of question mark).

**Option (C)30 is correct option.**

## Problem # 7

In this type of reasoning question either we have to study the pattern row wise or column wise. I mean to say that if we add or multiply all the numbers present in each row or column then its sum or product must be same.

It is not necessary that pattern will always be found by addition or multiplication of the numbers present in rows or columns.

Sometimes the pattern can be found of with the help of another logics like L C M or H C F of the numbers present in specific row or column.

But in this problem if we find the product of all the numbers in every column, then it is same in every column.

So to find the value of question mark in 4th row, then we have to find the product of all the 1st three columns.

**Product of all the numbers in every column is 120.**

6 × 1 × 10 × 2 = 120 ( Last Column )

2 × 12 × 3 = 120 ( 2nd Last Column )

3 × 40 = 120 ( 2nd Column )

Hence the value of "?" must be 120

**Option (4)120 is correct option.**

## Problem # 8

This box problem of reasoning consist of three rows and three columns. And we have to find the value of question mark after studying the pattern of all the letters in this box.

If we start assigning all the letters of alphabet to numbers serial wise from 1 to 26. Then the value of the letters present in the box above have these values .

C = 3 , E = 5 , D = 4 , K = 11 , F = 6, J = 10

Now we can easily find the value of the number present in 3rd column using the value of two other numbers we just got letter,s value.

**In 1st Row**

C and E = C + (C × E) = 3 + (3 × 5) = 3 + 15 = 18

**In 2nd Row**

D and K = D + (D × K) = 4 + (4 × 11) = 4 + 44 = 48

**In 3rd Row**

F and J = F + (F × J) = 6 + ( 6 × 10 ) = 6 + 60 = 66

**The correct Answer is option (B)66.**

## Problem # 9

This box problem of reasoning also consist of three rows and three columns. And we have to find the value of question mark present in 3rd row of 3rd column after studying the pattern or formula of all the letters in this box.

If we start assigning all the letters of alphabet to numbers serial wise from 1 to 26. Then the value of the letters present in the box above have these values .

C = 3 , E = 5 , D = 4 , K = 11 , F = 6, J = 10

Now we can easily find the value of the number present in 3rd column using the value of two other numbers we just got letter,s value.

**In 1st Row**

D + T = 4 + 20 = 24

**In 2nd Row**

G + S = 7 + 19 = 26

**In 3rd Row**

M + X = 13 + 24 = 37

**The correct Answer is option (1)37.**

## Problem # 10

This box problem of reasoning consist of four rows and three columns . And we have to find the value of question mark which is lying in third row of third column after studying the pattern of all the numbers in this box.

Because after careful observation we can see that the sum of

**of numbers in 1st and 2nd rows and**__squares__**of 3rd row is equal to the number in 4th row.**__cube__**Formula:-**

**(Number in 1st row)² + (Number in 2nd row)² + (Number in 3rd row)³ = (Number in 4th row)**

## 1st column

4² + 7² + 2³ = 16 + 49 + 8 = 73

**2nd column**

9² + 3² + 1³ = 81 + 9 + 1 = 91

**3rd column**

6² + 2² + 3³ = 36 + 4 + 27 = 67

**The correct Answer is option (1)67**

**Conclusion**

So these were the Ten Most Important Reasoning questions with answers for competitive exams of number analogy with solutions were discussed in this post . These types of problems are very helpful for cracking competitive exams like ssc cgl, ssc chsl and various Bank exams and many other similar exams. Please feel free to comment your opinions.

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