Reasoning of missing number in box problems, circle problems and triangle problems will be discussed with the help of 10 most important examples. Some of these examples are of 4 × 4 order and other are of 4 × 3 orders.

Reasoning of missing number in box problems in Uniteted State

**PROBLEM # 1**

Formula

### Calculation

**Option (D)1 is correct option.**

**PROBLEM # 2 **

Formula

### Calculation

**Option (A)745 is correct option.**

**PROBLEM # 3 **

__same formula will be applicable__to third figure to find out the value of question mark.

**Formula**:- The

__DIFFERENCE__of squares of both the numbers in empty box in upper line in every figure is equal to number in dark box in lower line.

**Solution:-**

9² - 6² = 81 - 36 = 45 (1st Figure)

8² - 2² = 64 - 4 = 60 (2nd Figure)

7² - 3² = 49 - 9 = 40 (3rd Figure)

**Option (1)40 is correct option.**

**PROBLEM # 4 **

__same formula will be applicable__to third figure to find out the value of question mark.

**Formula**:- The

__SUM__of squares of both the numbers in empty box in upper line in every figure is equal to number in dark box in lower line.

**Solution:-**

9² + 6² = 81 + 36 = 117 (1st Figure)

8² + 2² = 64 + 4 = 68 (2nd Figure)

7² + 3² = 49 + 9 = 58 (3rd Figure)

**Option (1)58 is correct option**

**PROBLEM # 5 **

√? = 30/6 = 5, squaring both sides

**Option (A)25 is correct option**

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PROBLEM # 6

∛? × ∛343 = ∛? × 7 = 14

∛? = 14/7 = 2 cubing both sides

**Option (C)8 is correct option**

**PROBLEM # 7 **

__same formula will be applicable__to third figure to find out the value of question mark.

**Formula:-**Add all the numbers in the corner of each figure to get value of the number in the middle.

**Solution:-**

**Option (3)17 is correct option**

## Reasoning of missing number in circle problems

**PROBLEM # 8**

This circle consists of four quadrants and every quadrant consists of three numbers . And every quadrant have two numbers in outer part and one number in the inner part . To find the value of question mark "?" , we shall use two numbers which are in the outer part to calculate the value of the number which is in the inner part of every quadrant .

### 1st Quadrant

**Step 1.** Take sum of the squares of both the numbers (8 and 4 ) in outer part of this quadrant.

**Step 2.** Take the magnitude of difference of both the numbers in outer part of this quadrant.

**Step 3.** Divide the result obtained in step 1 with the result obtained in step 2 to get the value of the number (20) in inner part of this quadrant.

### Calculation

(8² + 4² ) ÷ ( |8 - 4 |) = ( 64 + 16 ) ÷ 4 = 80 ÷ 2 = 20

### 2nd Quadrant

**Step 1.** Take sum of the squares of both the numbers ( 7 and 5 ) in outer part of this quadrant.

**Step 2.** Take the magnitude of difference of both the numbers in outer part of this quadrant.

**Step 3.** Divide the result obtained in step 1 with the result obtained in step 2 to get the value of the number (37) in inner part of this quadrant.

### Calculation

(5² + 7² ) ÷ (|5 - 7 |) = ( 25 + 49 ) ÷ 2 = 74 ÷ 2 = 37

### 3rd Quadrant

**Step 1.** Take sum of the squares of both the numbers ( 10 and 6 ) in outer part of this quadrant.

**Step 2.** Take the magnitude of difference of both the numbers in outer part of this quadrant.

**Step 3.** Divide the result obtained in step 1 with the result obtained in step 2 to get the value of the number (34) in inner part of this quadrant.

### Calculation

(10² + 6² ) ÷ ( |10 - 6| ) = ( 100 + 36 ) ÷ 4 = 136 ÷ 4 = 34

### 4th Quadrant

**Step 1.** Take sum of the squares of both the numbers ( 10 and 6 ) in outer part of this quadrant.

**Step 2.** Take the magnitude of difference of both the numbers in outer part of this quadrant.

**Step 3.** Divide the result obtained in step 1 with the result obtained in step 2 to get the value of the number (34) in inner part of this quadrant.

### Calculation

(6² + 4² ) ÷ ( |6 - 4 |) = ( 36 + 16 ) ÷ 2 = 52 ÷ 2 = 26

**Option (3)26 is right option**

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Box Problems

**PROBLEM # 9 **

**add these two adjacent numbers then reverse of order of the result so obtained then this number will be equal to the number in small circle opposite to both these numbers .**

**Option (B)13 is right option**

## Reasoning of missing number in triangle problems

**PROBLEM # 10 **

__same formula will be applicable__to third figure to find out the value of question mark.

**Formula**:- One tenth of the product of two outer numbers in each triangle is equal to third number .

**1st Triangle**

**2nd Triangle**

**3rd Triangle**

**Option (3)9 is correct option**

Ten Most Important Reasoning questions with answers for competitive exams of series , box and other type with solutions have been discussed in this post . These types of problems are very helpful for cracking competitive exams like ssc cgl, ssc chsl and various Bank exams and many other similar exams. please feel free to comment your opinions

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