Showing posts with label Others. Show all posts
Showing posts with label Others. Show all posts

Ten most important questions of Reasoning Analogy in missing numbers in various figures


Ten most Important questions of Reasoning Analogy of missing numbers have been discussed with their Solutions in an easy manners. These questions are very very important for competitive exams like SSC CGL , SSC CHSL And RRB NTPC Etc Because such types of problems are frequently asked in these exams.

 Problem #1  



Moving clock wise from top right number , Double the top right number to get bottom right number and add 2 to get bottom left number, now again double this number to get top left number in all the three figures .

Hence in  option (4)  24  is right answer

    Problem #2




Multiply  all the numbers which are on the corners of the given triangles to get the number which is on the centre of particular triangle.
In 1st triangle  multiply all the numbers on the corner of triangle
1 × 2 × 3 = 6
Again In 2nd  triangle  multiply all the numbers on the corner of triangle
2 × 5 × 3 = 30
Similarly In 3rd  triangle  multiply all the numbers on the corner of triangle
4 × 8 × 5 = 160

Hence in  option (3)  160  is right answer

Problem #3



If we add the top and bottom  numbers and the subtract from it the sum of left  and right  terms we shall get the middle number in all the figures.
in 1st figure
(3+7) - (2+5) = 10 - 7 = 3 ( Middle number in 1st figure) 
In 2nd figure
(9+9) - (7+8) =18 -15 = 3( Middle number in 2nd figure) 
In 3rd figure 
(8+8) - (6+6) = 16 -12 = 4( Middle number in 3rd figure) 

Hence in  option (2) 4 is right answer

Problem # 4




Multiply the top numbers and bottom numbers row wise the take the difference  of it .
In 1st figure 
( 5 × 6 ) - ( 3 × 8) = 30 - 24 = 6 ( Middle number in 1st figure) 

2nd figure
( 10 × 4 ) - ( 2 × 7 ) = 40 - 14 = 26 (Middle number in 2nd figure) 

3rd figure 
( 9 × 7 ) - ( 6 × 8 ) = 63 - 48 = 15 ( Middle number in 3rd figure) 

Hence in  option (2)  15  is right answer

Problem #5 



Cross multiply the numbers to get middle number in all the figures .


In 1st figure 

12 × 5 = 15 × 4 = 60 ( Middle number in 1st figure) 

In 2nd figure
3 × 14 = 6 × 7 = 42 ( Middle number in 1st figure)

In 3rd figure
26 × 3 = 13 × 6 = 78
 ( Middle number in 1st figure)

Hence in  option (3)  78 is right answer

Problem #6 




Take cube roots of all the numbers which are on outer side 
 all the ellipse ( given figure ) and then add these numbers  to get middle number in the figure .

In 1st figure  cube roots of 1, 64, 27 and 8 are 1 , 4 , 3 and 2 respectively. 

Now add these numbers. i.e 1 + 4 + 3 +2 = 10
In 2nd figure  cube roots of 8, 125, 64 and 27  are 2 , 5 , 4 and 3 respectively. 

Now add these numbers. i.e 2 +5 + 4 +3 = 14
Similarly In 3rd figure  cube roots of  27 , 216 , 125 and 64 are 3 , 6 , 5 and 4 respectively. 
Now add these numbers. i.e 3 + 6 + 5 + 4 = 18

Hence in  option (4)  18  is right answer

Problem #7 



In all the figure add both numbers which are 2nd and 3rd rows then multiply this result with the number which is on the right side of given figure in the 1st row to get the number on the left side of 1st row of given figure.
In 1st figure 1 + 2 =》3 × 9 = 27
In 2nd figure  2 + 3  =》 5 × 7  = 35
In 3rd  figure  x + 4  =》 (x+4) × 4 = 36
 4x + 16 = 36
 4x = 36 - 16 = 20
x = 5

Hence in  option (3)  5  is right answer

Problem #8 




1st Figure


 From 1st figure we can see that lower number is thrice (3 times) of sum ( addition ) of both numbers which are on upper portion of figure i. e . 18 + 9 = 27 .
Now multiply it with 3 , we get 27 ×3  =81 , which is the lower number in 1st figure.

3rd Figure

And for third  figure add both the numbers 24 and 7 and then multiply  the sum with 3 like this 24 + 7 = 31 and 31 × 3 = 93

2nd  Figure

Similarly ?  in 2nd figure can be found by adding 23 and 8 and then Multiply  it with 3 as follows 

     23 + 8 = 31 × 3 = 93 , Hence 93 is the required number.

Hence in  option (3)  93  is right answer

Problem #9 




From 1st two  figures if we multiply top and bottom terms and then subtract  the result of product of left and right terms from it we shall get the number in the middle of the circles in both the given figures.
( 6 × 7 ) - ( 4 × 5 ) = 20 ( Middle Number in 1st Figure ) . 
( 9 × 7 ) - ( 6 × 3 ) = 45 ( Middle Number in 2nd Figure ). 
Similarly middle number of 3rd figure can be calculated as follows
( 8 × 8 ) - ( 4 × 6 ) = 40 ( Middle Number in 3rd Figure )

Hence in  option (3)  40  is right answer

Problem #10



If we add the left and right  numbers and the subtract from it the sum of top and bottom  terms we shall get the middle number in all the figures
( 5 + 6 ) - ( 4 + 7) = 0
( 7 + 6 ) - ( 8 + 4 ) = 1
similarly 3rd term can be calculated as follows
( 11 + 2 ) - ( 0 + 2 ) = 11

Hence in  option (3)  11  is right answer


How-to-Solve-hard-and-impossible-Puzzles


TO CRACK  ANY COMPETITIVE EXAM VISIT THIS YOU TUBE CHANNEL FOR MATHS AND REASONING 

EXAM CRACKER


My previous Post



FINAL WORDS


  Thanks for watching and responding to this post of reasoning based on mathematics and number sequence puzzle solver.


Appeal 


If you are a mathematician Don't forget to visit my Mathematics You tube channel ,Mathematics Website and Mathematics Facebook Page , whose links are given below


Also watch this video


Share:

HOW TO ADD 1 TO 1000 NUMBERS VERY EASILY

HOW TO ADD 1 TO 1000 NUMBERS VERY EASILY

If you want to add 1 to 1000 then follow these two steps
Add 1 to last number 

2 Multiply last number and it's next numbers then divide by 2 . And thats it  .

अगर आप 1 से लेकर किसी भी अंतिम संख्या को जोड़ना चाहते हो तो सबसे पहले अंतिम संख्या में एक जोड़ दें फिर अंतिम संख्या और उससे आगे बाली संख्या को गुणा करके 2 से भाग दे दें ,आप इस तरह से कितनी भी शंख्ययाओं का जोड़ एक दम से कर सकते हो

उदाहरण

If we have to add 1st 50 numbers then  Multiply 50 with 51 and divide the product with 2 and it is the sum of 1st 50 natural numbers 

 अगर हम 1 से 50 को जोड़ना चाहें तो 50 और 51 गुना करके 2 से भाग देंगे
1 +2+3+4+5+6+7+……+50 =(50×51)÷2 = 25×51=1275
अगर हम 1 से 100 को जोड़ना चाहें तो 100 और 101 गुना करके 2 से भाग देंगे
1+2+3+4+5+…….+100=( 100×101) ÷2 =50×101=5050
अगर हम 1 से 1000 को जोड़ना चाहें तो 1000 और 1001 गुना करके 2 से भाग देंगे
1+2+3+4+5+…….+1000 =(1000×1001)÷2 = 500×1001= 500500
अगर हम 1 से 2000 को जोड़ना चाहें तो 2000 और 2001 गुना करके 2 से भाग देंगे
1+2+3+4+5+…….+2000=( 2000×2001)÷2 =1000×2001 = 2001000



How-to-check-divisibility-of-given Numbers



TO CRACK  ANY COMPETITIVE EXAM VISIT THIS YOUTUBE CHANNEL FOR MATHS AND REASONING 


EXAM CRACKER


  

FINAL WORDS


Thanks for watching and responding to this post "HOW TO FIND SUM OF 1ST N NATURAL NUMBERS ".


My previous Posts


Appeal



If you are a mathematician Don't forget to visit my Mathematics You tube channel , Mathematics Website and Mathematics Facebook Page , whose links are given below

Share:

A QUIZ OF MATHEMATICS FOR YOU ,MATRICES QUESTION PAPERS

A Quiz Of Mathematics For You 






There are Total 10 questions in all . Each question is assigned with 2 marks. Attempt all Question. Matrices question papers, determinant questions and answers, All the questions are from matrices and Determinants . Score will be Displayed at the end of Quiz.

TO CRACK  ANY COMPETITIVE EXAM VISIT THIS YOUTUBE CHANNEL FOR MATHS AND REASONING 

EXAM CRACKER

My previous Posts



FINAL WORDS


  Thanks for watching and responding to this quiz based on Matrices and Determinants on Mathematics. 


Appeal 


If you are a mathematician Don't forget to visit my Mathematics You tube channel ,Mathematics Website and Mathematics Facebook Page , whose links are given below


Share:

HOW TO SOLVE HARD AND IMPOSSIBLE PUZZLES PART 3

Let us  discuss some of the puzzles,  which are viral in social media such as Face book  ,whats app and twitter etc. which are based on Mathematics directly or indirectly . You also have seen such types of problems mentioned  99.9%  Fail , Solve if you are genius like this...


TODAY'S  PUZZLE FOR YOU

HOW TO  SOLVE   HARD  AND IMPOSSIBLE  PUZZLES   PART 3
I am fully hopeful that you can crack this puzzles , in case you are not able to crack/solve this , or want to confirm your answer you can click here .
Let us try to discuss and solve  some of the Puzzles given below  one by one.

PUZZLE #1 


Look at 1st Row, there is no direct connection between 9, S and 10. Also it seems no connection between 4, 5, M, 1, 3 in 2nd row ,Similarly 3, 1, 1,  L, 2 , ?, 1  have no direct connection between them.
But if we recall English Alphabet A,B,C,D,E,F,.. ..Y,Z and check that which letter is at 9th and 10th position, we shall find that this is not "S" .But let us check what is the position of Letter "S" in English alphabet. We find that it is in 19th position, as 9+10= 19 , It means that "S" is equal to 19.


How to solve puzzles


So now check the position of letter "M" , which is 13th , and the  sum of all the digits in 2nd Row is 4+5+1+3 = 13, Similarly we can check that 1+2+4+5=12, 12th is the position of letter "L" and  3+2=5 ,5th is the position of letter E.


So by this trend we can add all the digits in 3rd row and put its total equal to 8, as position of the letter "I" is 9th in English Alphabet. The difference between the position of the letter "I"  and total  of all the digits in same time must be equal to each other.

Therefore 1(one) is the digit to be occupied by ? 

PUZZLE 2


In this Puzzle we have five circles in all ,and some of them are overlapping each others , Look at 1st line 15,12,24 ,It seems no relation between these numbers.But if we  add all the numbers lying in any circles , then from 1st circle of 1st line we shall have 15 + 10 = 25 and from 3rd circle of 1st line we shall have 24 + 1 = 25 .

HOW TO  SOLVE   HARD  AND IMPOSSIBLE  PUZZLES   PART 3


Similarly from 2nd circle of 2nd line we shall have 4 + 1 + 20 = 25.
It means total of all the numbers lying in any circle must be 25 . So 
from 2nd circle of 1st line we shall have 12+? + 4= 25 implies that ? must be 9 and when we consider  1st circle of 2nd  line we shall have 10 + 6 + ? = 25 this also implies that  ?  must take the value 9.


So our  Answer will be 9

PUZZLE #  3



Look at 1st line if we subtract 1 from 1 ,we get 0 , we get our 1st line's answer . Same pattern should be followed in the next and remaining lines. But when we subtract  1 from 2 in 2nd line we get 1,which is not our answer. 

How to solve picture puzzles

So let us try  new pattern right from the 1st line. If we square the 1st number and then subtract the 2nd  number from it, Let us check it from 1st line .
12  - 1 = 1 ,      It is working for 1st line
22  - 1 = 3,      It is working for 2nd line
3 - 1 = 8,       It is working for 3rd line
42  - 1 = 15,     It is working for 1st line
52  - 1 = 24,  


So following the same pattern we can calculate answer

for the line containing 6 - 1 like this 
62  - 1 = 35

So our answer is  35.


The formula for this puzzle is x-1 = 
x2  - 1 ,
where x is the 1st number





PUZZLE # 4


From the 1st line it can be seen that 21 × 2 = 42, But 39 × 3 ≠ 618 .
so if we multiply 1st digit of left side with 2 then we shall have 4,6,2 as our  digit/digits in left side of answers and when we multiply 2nd digit with 2 , we shall have 2,18,14 as right side of answer .
HOW TO  SOLVE   HARD  AND IMPOSSIBLE  PUZZLES   PART 3
So we have to multiply with 2 on left side of our question to get left
digit and  multiply 5 with 2 to get 10 on right side of the answer.
Hence Our answer will for  45= (2×4)(2×5) = 810

The Formula for this Puzzle is  ab = (2a)(2b)

PUZZLE # 5


If we add all the digits , we can not get the answer .we have to try something new . But if we square the 1st number and add  both remaining numbers to it ,the we can get result of 1st line like this  2 + 3 + 4 = 22  +3 + 4 = 11.   
Let us check the same pattern for 2nd line 3 + 4 + 5 = 32  + 4 + 5 = 18, but 18 is not the answer . It means this will not work here.

Now we have to try one more formula for this puzzle .

If we multiply the 1st number with 2 and add both the

remaining  numbers to it.

HOW TO  SOLVE   HARD  AND IMPOSSIBLE  PUZZLES   PART 3

Let us check all the line respectively.


1st  line  is    2×2 + 3 + 4   = 11, which 
is right answer.

2nd line  is    2×3 + 4 + 5  =  15, which 
is right answer.

3rd line   is    2×4 + 5 + 6   = 19, which 
is right answer.

So let us follow this pattern to find 
the answer of    the given puzzle as
follows

4th line  is   (2×7) + 8 + 9 = 31, which is
 right answer.

So formula we can use for this puzzle a+b+c   =   2a+b+c



PUZZLE # 6

To solve this puzzle , multiply 1st two digits with each other to get 1st two digits of the answer, After that multiply 1st and last digits to get 3rd and 4th digits of the answer, Now  add the numbers formed from 1st two steps and subtract 2nd number from it, we shall  have 5th and 6th digits of the answer.

HOW TO  SOLVE   HARD  AND IMPOSSIBLE  PUZZLES   PART 3

1st line can be written as   (5×3)(5×2)(15+10-3) = 151222,
2nd line can be written as  (9×2)(9×4)(18+36-2) = 183652
3rd line can be written as  (8×6)(8×3)(48+24-6) = 482466
4th line can be written as  (5×4)(5×5)(20+25-4) = 202541
Similarly we can write last and final line 
Final line  can be written as  (7×2)(7×5)(14+35-2)=143547

Formula for this Puzzle is abc=(ab)(ac)(ab+ac-b)

Also read this

Solve-picture-problems-reasoning


PUZZLE 7


This problem is based on solution of linear equation of two variables. so it can be  solved as follows .

If we put A,B,C and D then 

we shall have following equations 
A + B = 8--------------------(1)
C - D  = 6--------------------(2)
A + C = 13-------------------(3)
B + D = 8--------------------(4)


HOW TO  SOLVE   HARD  AND IMPOSSIBLE  PUZZLES   PART 3

Now we have to solve these equations for A,B,C and D.
From eq (1) we have A = 8 - B  ,put this value of A in (3),
we get   - B + C = 13, Rewrite it 
              B - C = -5 --------------------(5)
Now  adding (2)  and (5) ,we get
C - D +  B - C = 6 - 5
B - D =  1 ---------------------(6)
Adding (4) and (6),we get 2B = 9  ⇒ B =  9/2 = 4.5
Putting the value of B in Eq (1), we get 
4.5  +  A = 8 A = 3.5 ,
Put  "A" in (3) ,we get C = 9.5
Put the value of  "B" in (4) 
4.5+ D = 8 D = 3.5  So Final Answers  are 

A = 3.5,         B = 4.5,       C = 9.5,          D = 3.5


Conclusion


Thanks for devoting your valuable time for this post "How to solve various puzzles ,Quizzes , Brain Teasers and challenges " of my blog . If you liked this this blog/post, Do Follow me on my blog and share this post with your friends . We shall meet again in next post with solutions of most interesting and mind blowing puzzles ,till then Good Bye.

Let us learn Multiplication , division , Arithmatic and simplification short cut ,tips and  tricks after buying this Book of Magical Mathematics .

                                                                                 
Share: